Implementing and Operating Cisco Wireless Core Technologies (WLCOR) Free Sample Questions

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350-101 Sample Questions

  1. Question 1

    Q1

    While evaluating a warehouse environment for a new Wi-Fi 6 deployment, an architect notes that the noise floor in the 5 GHz band is consistently measured at -92 dBm. The automated guided vehicles (AGVs) require a minimum Signal-to-Noise Ratio (SNR) of 25 dB to maintain the 64-QAM modulation required for their telemetry application. Based on these parameters, what is the minimum acceptable Received Signal Strength Indicator (RSSI) the AGVs must perceive?

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    Correct answer: B

    SNR (Signal-to-Noise Ratio) is calculated as the difference between the received signal strength (RSSI) and the noise floor. The formula is: SNR = RSSI - Noise Floor. To find the minimum RSSI, rearrange the formula: RSSI = SNR + Noise Floor. Given an SNR requirement of 25 dB and a noise floor of -92 dBm, the calculation is 25 + (-92) = -67 dBm.

  2. Question 2

    Q2

    During an outdoor point-to-point bridge installation, the field technician mounts one directional antenna vertically and the receiving antenna horizontally. Which RF phenomenon will severely impact the link budget in this scenario?

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    Correct answer: C

    Antenna polarization describes the orientation of the electric field of the radio wave. If a transmitting antenna is vertically polarized and the receiving antenna is horizontally polarized, there is a 90-degree mismatch. This results in cross-polarization loss, which can attenuate the signal by as much as 20 dB or more, severely degrading the link budget.

  3. Question 3

    Q3

    True or False: Equivalent Isotropically Radiated Power (EIRP) is calculated by adding the transmitter power to the antenna gain, and then subtracting any cable loss.

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    Correct answer: A

    True. EIRP is the total actual power radiated by the antenna. It is calculated as: EIRP = Transmitter Power (dBm) - Cable/Connector Loss (dB) + Antenna Gain (dBi).

  4. Question 4

    Q4Multiple answers

    To optimize a high-density auditorium, a wireless engineer is analyzing the impact of client device capabilities on the overall cell performance. Which TWO of the following statements accurately describe how client characteristics affect RF design? (Select TWO)

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    Correct answers: A, C

    Devices with fewer spatial streams (like 1x1 smartphones) have lower maximum data rates compared to 2x2 or 3x3 devices. Consequently, they take longer to transmit the same payload, consuming more valuable airtime and reducing overall cell capacity. Furthermore, mobile devices often have weaker transmit power, requiring APs to have excellent receive sensitivity to maintain symmetrical links.

  5. Question 5

    Q5

    An engineer is designing a wireless bridge using the following parameters:

    • AP Transmit Power: 15 dBm
    • Cable Loss at Tx: 2 dB
    • Tx Antenna Gain: 12 dBi
    • Free Space Path Loss: 110 dB
    • Rx Antenna Gain: 14 dBi
    • Cable Loss at Rx: 3 dB

    What is the expected Received Signal Level (RSL) at the receiving radio?

    graph LR TX[Tx Radio: 15 dBm] -- -2 dB Cable --> TA((Tx Ant: 12 dBi)) TA -. FSPL: -110 dB .-> RA((Rx Ant: 14 dBi)) RA -- -3 dB Cable --> RX[Rx Radio: ? dBm]
    Show answer & explanation

    Correct answer: A

    The Link Budget calculation formula is: RSL = Tx Power - Tx Cable Loss + Tx Antenna Gain - FSPL + Rx Antenna Gain - Rx Cable Loss.
    Calculation: 15 - 2 + 12 - 110 + 14 - 3 = -74 dBm. The visual flow in the question accurately represents this addition and subtraction chain.

  6. Question 6

    Q6

    According to the inverse square law and Free Space Path Loss (FSPL) principles, what happens to the RF signal strength every time the distance from the transmitting antenna is doubled in free space?

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    Correct answer: C

    According to the 6 dB rule, which is derived from the inverse square law of radio wave propagation, doubling the distance from the transmitter results in a loss of 6 dB of signal strength in a free-space environment. Conversely, halving the distance increases the signal by 6 dB.

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