Question 1
A hospital is upgrading its patient monitoring system, which requires two Category 6A cables and one OM4 duplex fiber optic cable to be run to each of 75 patient rooms from a new Telecommunications Room (TR). The design specifies 76mm (3-inch trade size) conduits for horizontal pathways. According to TIA-569-D, and assuming a standard outside diameter for these cables, what is the maximum number of these three-cable bundles that can be installed in a single conduit without exceeding the 40% fill ratio?
Answer and explanation
Correct answer: C
This question requires a calculation based on the cross-sectional area of the cables and the conduit. A 76mm (3-inch) conduit has a total internal area of approximately 4768 mm². The 40% fill area is 1907 mm². The approximate area of a Cat 6A cable is 55 mm² and an OM4 duplex cable is 25 mm². A bundle (2x Cat 6A + 1x OM4) has an area of (2 * 55) + 25 = 135 mm². Dividing the available fill area by the bundle area (1907 / 135) gives approximately 14.12. However, due to cable packing inefficiency (nesting), a derating factor must be applied. A more realistic calculation using cable packing formulas or standard tables indicates that approximately 10-11 such bundles can fit. Of the choices given, 10 is the most realistic and safe answer.